Objective
- Evaluate an integral over an infinite interval.
- Evaluate an integral over a closed interval with an infinite discontinuity within the interval
- Use the comparison theorem to determine whether a definite integral is convergent
Integrating over an Infinite Interval
- When integrating over an infinite interval, it is reasonable that we look at the behavior of the integral as the limit of integration approaches
or
Definition
Integrating over an Infinite Interval
- Let
be continuous over the interval .
- Let
be continuous over the interval . For both cases above, if the limit exists, then the improper integral converges.
If the limit does not exist, the the improper integral diverges.
- Let
be continuous over the interval and be any real number over the domain of . If both
and converges, then converges.
If either one or both of these two diverges, thendiverges
Integrating over a Discontinuous Integrand
- Consider the integral
, where is continuous over but discontinuous at . - To deal with this, we consider that
is continuous over . - However, we should also know that
must satisfy .
- However, we should also know that
- Therefore, for us to integrate this, we consider the one-sided limit as
approaches from the left.
- To deal with this, we consider that
- We can do similar approaches for any integral with a discontinuous integrand.
Definition
Integrating a Discontinuous Integrand
- Let
be continuous over . - Let
be continuous over . In each case, if the limit exists, then the improper integral converges.
If the limit does not exist, then the improper integral diverges.
- Let
be a point in . If is continuous over [a, b] except at point , then If both integrals
and converge, then converges.
If either one or both of them diverges, thendiverges.
Comparison Theorem
- By comparing two similar functions
and , we can simply compare them without evaluating if an improper integral diverges or converges.
Definition
Comparison Test for Improper IntegralsSuppose that for all
, .
- Case 1: If
:
- Then, this indicates that
must diverge as well. - Case 2:
converges to some value :
- Then, this means that
must converge to some other value that is less than or equal to .